MAG810中Q402作用？（附图）

liangshun

<p>24楼：</p><p>1、如果说Q402是提供工作电压的，类似于常见的降压型二次电源，那么高压包初级就根本不是这样的接法。</p><p>2、说Q401是控制逆程电容的容量，更加不妥，Q401明明是开关管，提供高压包的初级电流。如果要控制逆程容量，就一定要开关管与电容串联。</p><p>3、楼主所提供的810电路图，高压电路复杂些，请看一下30楼的796电路图，比较简单明了，解释一下两只开关管是如何推勉工作的？？？</p>

mfh

<p>遇到<span lang="EN-US">24</span>楼的垃圾真是扫兴！</p><p>以下是我对楼主的图较详细的理解，肯定有不对之处，请大家共同探讨。</p><p><span lang="EN-US">1&nbsp; </span>从<span lang="EN-US">C415</span>送来的行脉冲加至<span lang="EN-US">IC401&nbsp; 4</span>脚，这一脉冲起到触发与同步的作用，代表行工 作正常的信息。无此脉冲<span lang="EN-US">IC401&nbsp; 6</span>脚将无输出，高压电路不工作。</p><p><span lang="EN-US">2&nbsp;<b style="mso-bidi-font-weight: normal;">&nbsp;</b></span><b style="mso-bidi-font-weight: normal;">当<span lang="EN-US">IC401 6</span>脚输出的矩型脉冲为上升沿时</b>：</p><p><span lang="EN-US">&nbsp;&nbsp; a </span>这一上升电压将通过<span lang="EN-US">R426 </span>对<span lang="EN-US">C430</span>充电直至<span lang="EN-US">Q407</span>饱和导通，<span lang="EN-US">Q401</span>工作。由<span lang="EN-US">R426 C430 Q407</span>组 成的积分延时电路的目的是防止<span lang="EN-US">Q401 Q402 </span>同时导通。</p><p><span lang="EN-US">&nbsp;&nbsp; b </span>同时这个上升电压将通过<span lang="EN-US">D411</span>加至<span lang="EN-US">C402</span>确保<span lang="EN-US">Q402</span>管断。</p><p><span lang="EN-US">3&nbsp; </span><b style="mso-bidi-font-weight: normal;">当<span lang="EN-US">IC401 6</span>脚输出的矩型脉冲为下降沿时</b>：</p><p><span lang="EN-US">&nbsp;&nbsp; a&nbsp;&nbsp; Q401 G </span>极电荷通过<span lang="EN-US">D408</span>迅速泄放，<span lang="EN-US">Q401</span>关断。<span lang="EN-US">C403</span>上的电压通过<span lang="EN-US">IC401 R426 R427&nbsp; Q401 G </span>极到地的<span lang="EN-US">10K</span>电阻（图中未画）放电，<span lang="EN-US">Q407</span>截止。<span lang="EN-US">FBT</span>开始为<span lang="EN-US">C404</span>充电直至<span lang="EN-US">C404</span>上峰值为<span lang="EN-US">210V</span>与<span lang="EN-US">FBT 1 2 </span>脚自感电压之和。</p><p><span lang="EN-US"><span style="mso-spacerun: yes;">&nbsp;&nbsp; </span>b<span style="mso-spacerun: yes;">&nbsp; </span><span style="mso-spacerun: yes;">&nbsp;</span></span>同时矩型脉冲的下降沿也送到<span lang="EN-US">C432</span>上，通过<span lang="EN-US">C432</span>的微分作用<span lang="EN-US">Q409 B</span>极得到一个负的阶跃，<span lang="EN-US">Q402</span>瞬间导通，由于<span lang="EN-US">Q409<span style="mso-spacerun: yes;">&nbsp; </span>C</span>极继续维持高电位<span lang="EN-US">Q402</span>继续关断。导通时间是由<span lang="EN-US">R424</span>对<span lang="EN-US">C432</span>的充电时间决定，此时<span lang="EN-US">C432 </span>又成为了积分电容。当<span lang="EN-US">C432</span>充电完成后<span lang="EN-US">Q409</span>截止<span lang="EN-US">Q402 G</span>极得到一个开通信号，此时<span lang="EN-US">Q402</span>终于导通了。由<span lang="EN-US">C432 R423 R424 Q409 </span>组成的延时电路的目的是使当<span lang="EN-US">Q401</span>主开关管关断后延时一定的时间再开通<span lang="EN-US">Q402.</span></p><p><span lang="EN-US">4 <b style="mso-bidi-font-weight: normal;">Q402 </b></span><b style="mso-bidi-font-weight: normal;">为什么要延时</b>？</p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt;"><font face="Times New Roman"><span lang="EN-US"><span style="mso-spacerun: yes;">&nbsp; </span></span><span lang="EN-US" style="FONT-SIZE: 12pt;"><span style="mso-spacerun: yes;">&nbsp;&nbsp;&nbsp;&nbsp;</span></span></font><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">当</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">FBT</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">为</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">C404</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">充电直至</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">C404</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">上峰值为</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">210V</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">与</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">FBT 1 2 </font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">脚自感电压之和后</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">C404</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">将向</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">FBT 1<span style="mso-spacerun: yes;">&nbsp; </span>2 </font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">脚电感反向充电。</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">C404</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">上的电压由峰值逐渐回落，当</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">FBT 1</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">脚变为</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">210V</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">时即</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman"> FBT 1<span style="mso-spacerun: yes;">&nbsp; </span>2 </font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">脚等电位时，</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">C404</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">对</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">FBT</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">的充电过程完毕。</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">C404</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">的电能转化为</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">FBT</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">中的电磁能。</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">FBT </font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">将感应出</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">2 </font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">正</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman"><span style="mso-spacerun: yes;">&nbsp; </span>1</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">负的自感电压。此时通过延时的</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">Q402</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">在此刻导通，自感电流通过</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">Q402<span style="mso-spacerun: yes;">&nbsp; </span>D401<span style="mso-spacerun: yes;">&nbsp;&nbsp; </span>FBT 1</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">脚形成的回。</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><p></p></span></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt;"><span lang="EN-US" style="FONT-SIZE: 12pt;"><p><font face="Times New Roman">&nbsp;</font></p></span></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt;"><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman">5 <b style="mso-bidi-font-weight: normal;">Q402</b></font></span><b style="mso-bidi-font-weight: normal;"><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">起什么作用？</span></b><b style="mso-bidi-font-weight: normal;"><span lang="EN-US" style="FONT-SIZE: 12pt;"><p></p></span></b></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt;"><font face="Times New Roman"><b style="mso-bidi-font-weight: normal;"><span lang="EN-US" style="FONT-SIZE: 12pt;"><span style="mso-spacerun: yes;">&nbsp;</span></span></b><span lang="EN-US" style="FONT-SIZE: 12pt;"><span style="mso-spacerun: yes;">&nbsp; </span></span></font><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">我能接受</span><span style="FONT-SIZE: 12pt;"><font face="Times New Roman">
                        </font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">正方</span><span style="FONT-SIZE: 12pt;"><font face="Times New Roman">
                        </font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">与</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><font face="Times New Roman"> 30</font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">楼</span><span style="FONT-SIZE: 12pt;"><font face="Times New Roman">
                        </font></span><span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">的阻尼及动态阻尼的看法。同时也等待不同的答案。</span><span lang="EN-US" style="FONT-SIZE: 12pt;"><p></p></span></p>

正方

<p>其实mfh分析得很到位了，我再补充一些。</p><p>&nbsp;1， 当正脉冲到来时，一路通过D411和C402，R402加至Q402的G极确保Q402管断，同时正脉冲将通过R426 对C430充电直至Q407饱和导通，Q401工作。由R426 C430 组成的积分延时电路的作用，使Q401延时导通，目的是防止Q401 Q402 同时导通。</p><p>&nbsp;2，Q401导通后，变压器产生2脚正，1脚负的自感电势，同时C401放电。</p><p>&nbsp;3，脉冲过后Q401截止，此时LC产生并联谐振，L上的电势为，1正2负，此时变压器次级感应出的高压为ANODE正，7脚为负，产生高压。</p><p>&nbsp;4，脉冲过后，由于C432的作用，使Q409延时截止Q402延时导通，当电感上电势为2正1负时，由于Q402的导通，使震</p><p>荡停止，所以说它是起阻尼作用。</p><p>&nbsp;由于C402上的电压上升，Q402很快恢复截止。电路达到平衡后，等待下一个脉冲的到来。</p><p></p>

mfh

<p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt;"><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">谢谢正方管理员！</span></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt; TEXT-INDENT: 21.75pt;"><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">在我最尴尬气愤之时能站出来，我是真没想到它是这么个东西！</span></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt; TEXT-INDENT: 21.75pt;"><span lang="EN-US"><p><font face="Times New Roman">&nbsp;</font></p></span></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt; TEXT-INDENT: 21.75pt;"><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">另外我再补充一些，大家看我说的对否。</span></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt; TEXT-INDENT: 21.75pt;"><b style="mso-bidi-font-weight: normal;"><span lang="EN-US"><p><font face="Times New Roman">&nbsp;</font></p></span></b></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt; TEXT-INDENT: 21.75pt;"><b style="mso-bidi-font-weight: normal;"><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">为什么要这么复杂的阻尼电路？</span><span lang="EN-US"><p></p></span></b></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt; TEXT-INDENT: 21.75pt;"><span lang="EN-US"><font face="Times New Roman">1 </font></span><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">如果</span><span lang="EN-US"><font face="Times New Roman">LC</font></span><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">振荡不被完全的阻尼掉，</span><span lang="EN-US"><font face="Times New Roman">FBT 2</font></span><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">脚的感生电压将对电源产生影响，尽管有</span><span lang="EN-US"><font face="Times New Roman">L105 C105</font></span><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">等。因为电源取样自</span><span lang="EN-US"><font face="Times New Roman">210V</font></span><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">。</span></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt; TEXT-INDENT: 21.75pt;"><span lang="EN-US"><font face="Times New Roman">2</font></span><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">如果</span><span lang="EN-US"><font face="Times New Roman">LC</font></span><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">振荡不被完全的阻尼掉，</span><span lang="EN-US"><font face="Times New Roman">Q401</font></span><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">瞬间导通时</span><span lang="EN-US"><font face="Times New Roman">C404</font></span><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">上的电压将不确定，会导致电路工作紊乱。这也许能解释楼上朋友在去掉</span><span lang="EN-US"><font face="Times New Roman">Q402 </font></span><span style="FONT-FAMILY: 宋体; mso-ascii-font-family: &quot;Times New Roman&quot;; mso-hansi-font-family: &quot;Times New Roman&quot;;">做试验时所出现的现象。</span></p>

116837314

<p>先申明一下</p><p>我在这里回贴-----不针对任何人；不反拔任何人；&nbsp; 不骂任何人；别人骂我---我不返击，就让他骂去。</p><p>尊重管理人员有规章。</p><p>不论是新手还是老手都是好朋友！</p><p>以主贴意思为中心：</p><p>接24楼补叙：</p><p>当IC401第6脚输出脉冲信号为高电位时---论</p><p>一路经过反向器Q409输出一个反了向的带有上下沿的矩形脉冲，来控制Q402的开通。省--C432的工作说明）。</p><p>一路经过Q407后是一个类似锯齿一样的尖波，控制Q401的导能工作。（省---C430的工作说明）。（这一路有一个反向的二极管D408，在脉冲是低电位时D408正好能使Q401快速截止；在另一路中的D411的用途也是快速截止）。</p><p></p><p>以上是我个人的说法。 不指向任何人。</p><p></p>

8002

说Q402是动态阻尼 , 可以接受;但问题是为什么其它机却很少采用类似的电路? 比如索尼 ,总不能用省成本来解释吧? 难道有了二次电源又有什么大区别?&nbsp; 请指教.

花开富贵

<p>精辟！！！</p><p>爽！！！</p><p>mfh、正方管理员、swl928用我能看懂的分析让我明白了Q402的阻尼（动态阻尼或推挽）开关管的作用。</p><p>有这样的论坛可以交流真好！！！</p><p>行输出电路中的阻尼二极管阻尼掉初级电感与逆程电容的LC振荡，我觉得本意是避免形成衰减振荡，由B＋为行输出逆程振荡每个周期补充新的能量，使行包初级电感与逆程电容每个行周期内等幅振荡，这样有助于稳定高压。</p><p>但是使用这样复杂的阻尼电路有什么好处真是难于琢磨。</p><p>再次感谢管理员、mfh、swl928、116837314及liangshun的热心赐教！！！</p><p></p>

liangshun

<p>管理员、mfh、swl928、116837314和楼主，大家再来讨论一下，在30楼的796电路中，两只开关管并没有积分延时电路，几乎是并联在同一个激励脉冲上的，那么它又如何来使两只开关管有效工作呢？</p><p>796机虽然比810机的高压电路简化了，但实际上796机的高压电路故障率还是很低的，说明简化了的电路仍然高效。</p>

花开富贵

<p>38楼的疑问个人认为是这样的：激励脉冲到达时Q506导通Q517截止，对应行正程后半段，此时200V经Q506对行包3、2绕组充电得到3正2负的感应电压且逐渐增强；激励脉冲过后Q506截止Q517导通，Q506截止后3、2绕组自感电压反相为3负2正，由于D505反偏截止，故初级感应电压对逆程电容C513充电（磁→电），C513端电压逐渐升高形成逆程脉冲前半段；3、2绕组放电完毕后，C513端电压对3、2绕组充电（电→磁）（3脚为交流地），3、2绕组感应电压为2正3负且逐渐增强，C513端电压逐渐降低，形成逆程脉冲的后半段；C513放电完毕时，3、2绕组感应电压反相为3正2负，该电压经导通的Q517及D505放电，3、2绕组与C513的电磁振荡被阻尼掉，能量释放完毕，对应行正程前半段，等待下一个激励脉冲到达。</p><p>如有不妥，敬请指正！！！</p>

花开富贵

<p><font face="楷体_GB2312" size="4">38楼的疑问个人认为是这样的：激励脉冲到达时Q506导通Q517截止，对应行正程后半段，此时200V经Q506对行包3、2绕组充电得到3正2负的感应电压且逐渐增强；激励脉冲过后Q506截止Q517导通，Q506截止后3、2绕组自感电压反相为3负2正，由于D505反偏截止，故初级感应电压对逆程电容C513充电（磁→电），C513端电压逐渐升高形成逆程脉冲前半段；3、2绕组放电完毕后，C513端电压对3、2绕组充电（电→磁）（3脚为交流地），3、2绕组感应电压为2正3负且逐渐增强，C513端电压逐渐降低，形成逆程脉冲的后半段；C513放电完毕时，3、2绕组感应电压反相为3正2负，该电压经导通的Q517及D505放电，3、2绕组与C513的电磁振荡被阻尼掉，能量释放完毕，对应行正程前半段，等待下一个激励脉冲到达。</font></p><p><font face="楷体_GB2312" size="4">如有不妥，敬请指正！！！</font></p>

mfh

<p><span lang="EN-US">liangshun </span>你好！我感觉你把图纸弄混了。我下载楼主的图右下脚 型号是<span lang="EN-US">796PF</span>，应该是你所说较复杂的<span lang="EN-US">810</span>，而你认为比较简单的<span lang="EN-US">796</span>应该是<span lang="EN-US">810</span>。</p><p>我在图纸美格区下了<span lang="EN-US">MAG810 </span>虽然图不清楚但能和你认为的<span lang="EN-US">796</span>对上号。</p><p>我看了这两张图纸的出图时间（在右下脚），电路较简单的<span lang="EN-US">810 </span>是<span lang="EN-US">99</span>年，较复杂的<span lang="EN-US">796PF </span>是<span lang="EN-US"> 01</span>年，时间相差<span lang="EN-US">2</span>年。电路上可能相差了一两代。</p><p>我觉得是较复杂是对较简单的改进，较复杂的加了延时电路，提高了电路的可靠性。较简单的没有延时电路，当有外部干扰时有可能两管同时导通，开关管得不到保护。</p><p>忽然想到如果把<span lang="EN-US">Q407 Q409</span>等均定义为保护电路会怎样，大家看如何？</p>

liangshun

<p>我所指的796机型其实是796FD，与810FD的高压电路比较相似，而楼主在标题处提到的MAG810却用了796PF的图，所以我搞错了，以为后期的810电路作出了改进。796FD和796PF完全是两个电路结构，前者用SONY显象管，99年产品，后者用美格显象管，01年产品。41楼说得正确，796PF对796FD的高压电路作出改进，包括采用3843以获得更理想的方波，并加入延时激励电路。</p>

mfh

<p>&nbsp; 其实796FD 810DF 我没有接触过，对图纸对号也很混乱。</p>